php - Return True or False & how to get just on true in a loop -


i have script sends via $.post information

$("#clickme").click(function(e){   var selected = $(".img input:checked").map(function(i,el){return el.name;}).get(); var prelucrare = selected.join(";") $.post('test.php', {     rezultat: prelucrare,     },  function(data){     $('#rez').html(data) });   });`

and php file handles $.post

<?php require_once '../config.php'; if(isset($_post['rezultat'])) { $d = explode(';', $_post['rezultat']);  foreach($d $numar_inregistrare){     $sql = "delete galerie_foto numar_inregistrare = '$numar_inregistrare'";     $rezultat = mysql_query($sql) or die(mysql_error());      return true;           } } else { exit; } ?>

i have 2 questions: 1. how can make js script thing if return value true , other thing if return value false ? ?

  $.post('test.php', {   rezultat: prelucrare,        success: function(msg){         valid = (msg == 1) ? true : false;         if(!valid) {             $("#valid_input").html("please enter valid info");         } else {             $("#valid_input").html("");         }      }    )};
  1. my other question returning result, because i'm in loop if there 3 things in array result truetruetrue instead of 1 true, can make 1 true ?

you can use "return" in functions , methods. print "true" or "false" once, in foreach loop can break out or in case exit 'false' if there's error. you'll have this:

foreach($d $numar_inregistrare){     $sql = "delete galerie_foto numar_inregistrare = '$numar_inregistrare'";     $rezultat = mysql_query($sql);      if (!$rezultat) {         exit('false');     } }  echo 'true';  ....

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