Getting date format in xslt -
i have xslt code getting date.my code like
<xsl:copy-of select="substring-before(msxsl:node-set($notes)/root/item/lastchanged,'t')"/>
her got output 2013-04-05
but need output 15 jan 2013.
how can achive this?any 1 help
just change order
xslt
<?xml version='1.0'?> <xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/xsl/transform" xmlns:ms="urn:schemas-microsoft-com:xslt" xmlns:dt="urn:schemas-microsoft-com:datatypes"> <xsl:template match="/"> <html> <head> </head> <body> <xsl:for-each select="xmlsamples/filedetails/date"> <div> date unedited: <xsl:value-of select="."/> </div> <div> date edited: <xsl:value-of select="ms:format-date(., 'mmm dd, yyyy')"/> </div> </xsl:for-each> </body> </html> </xsl:template> </xsl:stylesheet>
output
date unedited: 2000-02-16t15:56:00
date edited: feb 16, 2000
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