Passing a string array to a function in C -

i learning c, explain why following code produces segmentation fault after printing first element of array?

what working code like?

#include <stdio.h> #include <stdlib.h> #include <string.h>  #define elements 8  void make(char ***array) {  *array = malloc(elements * sizeof(char *));       (*array)[0] = "test0";     (*array)[1] = "test1";     (*array)[2] = "test2";     (*array)[3] = "test3";     (*array)[4] = "test4";     (*array)[5] = "test5";     (*array)[6] = "test6";     (*array)[7] = "test7";     (*array)[8] = "test8";  }  int main(int argc, char **argv)  { char **array; make(&array);  int i; (i = 0; < elements; ++i) {     printf("%s\n", array[i]);     free(array[i]); } free(array); return 0; 

}

when put literal string in c++ "test0", stored in special memory location cannot modified. in line

(*array)[0] = "test0"; 

you're pointing char* memory location, alright do. however, later, when call free(array[i]);, attempting free same memory, no-no. in general, use free() if have used malloc() on same variable.

also, others have said, need allocate array of size 9, since you're using 9 elements.