Python furl library - Is there a way to add a parameter to a url without url encoding it? -

i have url need add api key parameter. key has % , other characters in , should not url encoded, there way furl?

heres current code:

request_url = furl('http://www.domain.com/service/') \     .add({     'format'     : 'json',     'location'      : address_line_1 + ',' + city + ',' + state,     'key'           : app_key }).url 

i have url need add api key parameter. key has % , other characters in , should not url encoded

that can't true. must url-encoded. otherwise, end either invalid url, or url doesn't mean wanted.

for example, let's key 123%456%789. if send http://www.domain.com/service/?format=json&key=123%25456%25789, web service on other end 123%456%789, succeed. if send http://www.domain.com/service/?format=json&key=123%456%789, web service on other end 123e6x9, fail.

so, example correct, , shouldn't need anything.

if, reason, you're url-encoding app_key before here… well, don't. name that, i'm guessing it's constant literal copied , pasted module, means had manually url-encode , copy , paste result. don't that, , you're fine.

if got app_key in url-encoded form, can decode with, e.g., urlparse.parse_qs, or furl.

but if none of seems reasonable…

is there way furl?

no. see encoding section of docs. furl works on decoded query string names , values.

but there's easy way around this. url isn't complicated of thing, , furl designed allow mix , match manually- , programmatically- created bits. of examples in readme show that, such furl('http://www.google.com/?one=1').add({'two':2}).url. so, if you've got pre-encoded "key=123%25456%25789" somewhere, stick on string manually before giving furl:

request_url = furl('http://www.domain.com/service/?key={}'.format(app_key)) \     .add({     'format'     : 'json',     'location'      : address_line_1 + ',' + city + ',' + state, }).url 

hacky? well, yes, in you're side-stepping furl's encoding, that's you're asking how do.