Bash function, export function argument as environment variable -

i wrote bash function export environment variable. first function argument variable name, second variable value. want echo show value exported:

#!/bin/bash  env_var_export() {     export $1=$2  echo "" echo "  export $1=$$1" echo "" }  env_var_export var defaultval456

i mean, echo should print: export var=defaultval456. help? know can this:

echo "" echo "  export $1=$2" echo ""

but not solution problem.

$$ special variable expands shell's pid, , that's going evaluated in echo. should instead use indirect reference this:

echo "" echo "  export $1=${!1}" echo ""

this syntax take variable named in $1 , lookup value based on name (i.e. indirection).

Bready