java - Ordering of instance variable initializers -

it seems intuitively clear in java, instance variable intitializers executed in order in appear in class declaration.

this appears case in jdk using. example, following:

public class clazz {     int x = 42;     int y = this.z;     int z = this.x;     void print() {         system.out.printf("%d %d %d\n", x, y, z);     }     public static void main(string[] args) {         new clazz().print();     } } 

prints 42 0 42 (in other words, y picks default value of z).

is ordering guaranteed? i've been looking through jls, , can't find explicit confirmation.

yes, is.

the se7 jls covers instance variable initialization order in 12.5 execution section:

...
4. execute instance initializers , instance variable initializers class, assigning values of instance variable initializers corresponding instance variables, in left-to-right order in appear textually in source code class. if execution of of these initializers results in exception, no further initializers processed , procedure completes abruptly same exception. otherwise, continue step 5.
...

the jls java 5 mentions in "classes" section:

the static initializers , class variable initializers executed in textual order.