php - How do you replace multiple instances of a preg_match matches with different replacement text? -

i have script runs through text input user , replaces text contained in tags html. works fine 1 of tags giving me trouble.

[include=somefile.php] should load contents of somefile.php page, [inlude=thatfile.txt] should load thatfile.txt. however, when there multiple instances of include tag, each 1 referring different files, replacing them 1 of included files. code using this...

if (preg_match ("/\[include=(.+?)\]/", $text, $matches)) {   foreach ($matches $match) {     $match = preg_replace("/\[include=/", "", $match);     $match = preg_replace("/\]/", "", $match);     $include = $match;     $file_contents = file_get_contents($include);     $text = preg_replace("/\[include=(.+?)\]/", "$file_contents", $text);   } } 

the last line of foreach loop seems replacing every instance of matched tags whatever finds in current tag don't know it. advice appreciated!

edit: uby made following changes , works now.

if (preg_match_all ("/\[include=(.+?)\]/", $text, $matches)) {      foreach ($matches[0] $match) {         $file = preg_replace("/\[include=/", "", $match);         $file = preg_replace("/\]/", "", $file);         $file_contents = file_get_contents($file);         $text = str_replace("$match", "$file_contents", $text);     }  } 

preg_match() match 1 occurrence, in case should use preg_match_all() (see documentation http://php.net/manual/en/function.preg-match-all.php)

read documentation, loop wouldn't work this.