Comparing Exception Objects in Python -

i new @ python , i'm stuck @ problem. trying compare 2 "exception objects", example:

try:     0/0 except exception e:     print e >> integer division or modulo 0  try:     0/0 except exception e2:     print e2 >> integer division or modulo 0  e == e2 >> false  e e2 >> false 

how should perform comparison obtain "true"?

what trying do:

class foo():     def bar(self, olderror = none):         try:             return urllib2.urlopen(somestring).read()                            except urllib2.httperror e:             if e.code == 400:                 if e != olderror: print 'error one'             else:                 if e != olderror: print "error two"             raise          except urllib2.urlerror e:              if e != olderror: print 'error three'              raise  class someclass():             # @ point called thread     def threadloop(self, stopthreadevent):         olderror = none         while not stopthreadevent.isset():             try:                 = foo().bar(olderror = olderror)             except exception e:                 olderror = e             stopthreadevent.wait(3.0) 

(probably syntax error)

why doing that? because don't want print same error twice

with exception classes, can test functional equality with

type(e) type(e2) , e.args == e2.args 

this tests classes identical, , contain same exception arguments. may not work exception classes don't use args, knowledge, standard exceptions do.