jquery - Ajaxed page does not render jquermobile style -


the following jquery code works not display jquerymobile select form. display plain select html. how can make bind ajaxed page render jquerymobile select form.

thanks in advance.

echo '<div data-role="fieldcontain" id="subject">'."\n"; echo '<label for="subjectid"><em>* </em> subject: </label>'."\n"; if(!empty($subjectlist)) {     echo form_dropdown('subjectid', $subjectlist,  null, 'id="subjectid" class="required" data-theme="c"')."<br />\n"; } else {     echo "no subject registered. contact application administrator."; } echo "</div>\n\n";   echo '<div data-role="fieldcontain" id="teachernamediv">'."\n";  echo "</div>\n\n"; .... ....  <script> $(document).ready(function() {     $('#loader').hide();     $('#teachernamediv').hide();      $('#subjectid').change(function(){         $('#loader').show();         var findteacher = "<?php echo base_url();  ?>index.php/welcome/user/findteacher";         $.post(findteacher, {             subjectid: $('#subjectid').val(),             teachergrp: "5",             user_id: $('input[name=id]').val(),         }, function(response){             settimeout("finishajax('teachername', '"+escape(response)+"')", 200);         });         return false;     }); });  function finishajax(id, response){  $('#loader').hide();  $('#'+id+'div').html(unescape(response));  $('#'+id+'div').fadein(); } <script>

and user.php

function findteacher() {     if($_post['subjectid'])     {         //$grade = $_post['grade'];         $subject_id = $_post['subjectid'];         $teachergrp = $_post['teachergrp'];         $user_id = $_post['user_id'];          // check if student has techerid in hw_user_subject subjectid         $findteacher = $this->mhomework->findsubjectteacher($user_id, $subject_id);         if(!empty($findteacher))         {             $data['teacher']=$findteacher;             $data['header']=$this->preference->item('site_name');         $this->load->view('common/teacher', $data);         }         else         {             // if there no teacher list of teacher names         $data['teachers'] = $this->mhomework->findteacher($subject_id,$teachergrp);            $data['header']=$this->preference->item('site_name');         $this->load->view('common/teachers', $data);          }      }     else     {         redirect ('welcome','refresh');     }  }

this teachers.php

echo '<label for="teachername"><em>* </em> subject teacher: </label>'."\n"; $option = array (         ''=>'-- select teacher --'          ); foreach($teachers $row) {     $gender=get_gender($row['gender']);     $option [$row['user_id']]=$gender." " . $row['last_name']; }   echo form_dropdown('teachername', $option,  null, 'id="teachername" class="required" data-theme="c" ')."<br />\n";

you have refresh selectmenu, html part displaying without runtime jquery, need refresh refresh() in jquery mobile...

check this:- http://api.jquerymobile.com/select/#method-refresh

this used update custom select reflect native select element's value. if number of options in select different number of items in custom menu, it'll rebuild custom menu.


Comments

Post a Comment

Popular posts from this blog

ios - iPhone/iPad different view orientations in different views , and apple approval process -

i force app's home screen portrait , other views landscape. apple rejects app if this? if not , how force first screen launch in portrait mode? , force other screens launch in landscape. this not duplicate question search every possible answer in website. i force app's home screen portrait , other views landscape. apple rejects app if this? no apple not reject app this. have lot of apps doesn't support orientation. forcing on 1 screen won't cause app reject. if not , how force first screen launch in portrait mode? , force other screens launch in landscape. can on write : -(nsuinteger)supportedinterfaceorientations; function.
Read more

java Extracting Zip file -

i'm looking way extract zip file. far have tried java.util.zip , org.apache.commons.compress, both gave corrupted output. basically, input zip file contain 1 single .doc file. java.util.zip: output corrupted. org.apache.commons.compress: output blank file, 2 mb size. so far commercial software winrar work perfectly. there java library make use of this? this method using java.util library: public void extractzipnative(file filezip) { zipinputstream zis; stringbuilder sb; try { zis = new zipinputstream(new fileinputstream(filezip)); zipentry ze = zis.getnextentry(); byte[] buffer = new byte[(int) ze.getsize()]; fileoutputstream fos = new fileoutputstream(this.tempfolderpath+ze.getname()); int len; while ((len=zis.read(buffer))>0) { fos.write(buffer); } fos.flush(); fos.close(); } catch (filenotfoundexception e) { // todo auto-generated catch block ...
Read more

C# WinForm - loading screen -

i ask how make loading screen (just picture or something) appears while program being loaded, , disappears when program has finished loading. in fancier versions, have seen process bar (%) displayed. how can have that, , how calculate % show on it? i know there form_load() event, not see form_loaded() event, or % property / attribute anywhere. all need create 1 form splash screen , show before main start showing landing page , close splash once landing page loaded. class splashform { //delegate cross thread call close private delegate void closedelegate(); //the type of form displayed splash screen. private static splashform splashform; static public void showsplashscreen() { // make sure launched once. if (splashform != null) return; thread thread = new thread(new threadstart(splashform.showform)); thread.isbackground = true; thread.setapartmentstate(apartmentstate.sta); thread....
Read more