xml - XSLT: Match N-level node -

need match node id. (say a2-2)

xml:

<node id="a" title="title a">   <node id="a1" title="title a1" />   <node id="a2" title="title a2" >     <node id="a2-1" title="title a2-1" />     <node id="a2-2" title="title a2-2" />     <node id="a2-3" title="title a2-3" />   </node>   <node id="a3" title="title a3" /> </node> <node id="b">   <node id="b1" title="title b1" /> </node> 

current solution:

<xsl:apply-templates select="node" mode="all">   <xsl:with-param name="id" select="'a2-2'" /> </xsl:apply-templates>   <xsl:template match="node" mode="all">     <xsl:param name="id" />     <xsl:choose>       <xsl:when test="@id=$id">         <xsl:apply-templates mode="match" select="." />       </xsl:when>       <xsl:otherwise>         <xsl:apply-templates mode="all" select="node">           <xsl:with-param name="id" select="$id" />         </xsl:apply-templates>       </xsl:otherwise>     </xsl:choose>   </xsl:template>    <xsl:template match="node" mode="match">     <h3><xsl:value-of select="@title"/>.</h3>   </xsl:template> 

problem:
above solution seem bulky quite common problem.
over-complicating? there simpler solution.

this solution twice shorter , simpler (a single template , no modes):

<xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/xsl/transform">  <xsl:output omit-xml-declaration="yes" indent="yes"/>  <xsl:strip-space elements="*"/>  <xsl:param name="pid" select="'a2-2'"/>   <xsl:template match="node">   <xsl:choose>    <xsl:when test="@id = $pid">     <h3><xsl:value-of select="@title"/>.</h3>    </xsl:when>    <xsl:otherwise><xsl:apply-templates/></xsl:otherwise>   </xsl:choose>  </xsl:template> </xsl:stylesheet>