python - Template directory logic in Django -

i've been fooling around templates time now, , loving every moment of django experience. however, since django such big fan loose coupling, wanted know, why not have piece of code:

import os import platform if platform.system() == 'windows':     templatefiles = os.path.join(os.path.dirname(__file__), '..', 'templates').replace('\\','/') else:     templatefiles = os.path.join(os.path.dirname(__file__), '..', 'templates') template_dirs = (     # includes templates folder     templatefiles, ) 

instead of:

import os template_dirs = (     templatefiles = os.path.join(os.path.dirname(__file__), '..', 'templates').replace('\\','/') ) 

would not first example follow philosophy of loose coupling better second (which believe does), , if so, why django default second code example , not first?

you ask, "why django default second code example?" in django 1.5, when run

$ django-admin.py startproject mysite 

i find settings.py contains:

template_dirs = (     # put strings here, "/home/html/django_templates" or "c:/www/django/templates".     # use forward slashes, on windows.     # don't forget use absolute paths, not relative paths. ) 

so not sure example code coming from: it's not django's default.

on non-windows systems rare find backslashes in directory names, second example work in practical cases. if had bullet-proof write:

import os base_dir = os.path.abspath(os.path.join(os.path.dirname(__file__), os.pardir)) template_dir = os.path.join(base_dir, 'templates') if os.sep != '/':     # django says, "always use forward slashes, on windows."     template_dir = template_dir.replace(os.sep, '/') template_dirs = (template_dir,) 

(using names os.pardir , os.sep make clear intend.)