html - How to get the position of a node based on the value of a child element -

in xml want specific menuitems/menuitem nodes @ different arbitrary positions under parent (i don't want hardcoded position selector).

is possible position of menuitem node has right value in name element under it, meaning menuitems/menuitem/name. in short: selecting menuitem has right name value under it.

<one>    <menuitems>       <menuitem>  <!-- dont want 1 -->          <name>            ...          </name>       </menuitem>        <menuitem>   <!-- want 1 @ position 2 under <one> -->          <name>             ...    <!-- based 1 correct name value here -->          </name>       </menuitem>    </menuitems>  </one> <two>   <menuitems>     <menuitem> <!-- want 1 @ position 1 under <two> -->        <name>           ...        </name>      </menuitem>    </menuitems> </two> 

i can find out if 1 menuitem under menuitems has correct name value. so:

 <xsl:value-of select="current()/menuitems/menuitem/name = 'ohyes'"></xsl:value-of> 

which return true. @ position menuitem amongs other menuitem returned true? selecting under same parent , @ same level.

i want avoid this:

<xsl:if test="current()/menuitems/menuitem[1]/name = 'ohyes'"> .. </xsl:if> <xsl:if test="current()/menuitems/menuitem[2]/name = 'ohyes'"> .. </xsl:if> 

use this:

<xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/xsl/transform">  <xsl:output omit-xml-declaration="yes" indent="yes"/>   <xsl:template match="/">   <xsl:for-each select="/*/*/menuitems/menuitem[name='ohyes']">    position: <xsl:text/>     <xsl:value-of select="count(preceding-sibling::menuitem) +1"/>   </xsl:for-each>  </xsl:template> </xsl:stylesheet> 

**when transformation applied on following xml document: ... --> ohyes --> ohyes

the wanted, correct result produced:

   position: 2    position: 1