php - Remove child array from array where child item is the last of that item -

my brain broken. here's concept:

$a = array('please', 2); $s = array('help', 3); $d = array('me', 1); $f = array('!', 3); $g = array('asdf', 1);  $myarray = array($a, $s, $d, $f, $g);  ($i = 0; $i < count($myarray); $i++) {     // code here } 

code should contain logic removes indexes 0, 3, , 4 myarray because contain last value of kinds (last 2, 3, , 1 respectively) @ position $myarray[$i][1].

--edit: adapted suggestions comments this:

$a = array('please', 2); $s = array('help', 3); $d = array('me', 1); $f = array('!', 3); $g = array('asdf', 1);  $myarray = array($a, $s, $d, $f, $g);  $used = array();  ($i = 0; $i < count($myarray); $i++) {     $used[$myarray[$i][1]] = $i; }  foreach ($used $deleteme)     unset($myarray[$deleteme]);  $newarray = array_values($myarray);  var_dump($newarray); 

it works, , creating new array array_values eliminates gaps created using unset().

$i = count($myarray); $used = array(); while ($i-- > 0)     if (!isset($used[$myarray[$i][1]])) {         $used[$myarray[$i][1]] = true;         unset($myarray[$i]);     } 

this simple snippet first iterates on array , deletes index if entry number wasn't deleted yet.