Using Boost C++ library to do a regex replace with a custom replacement -

i can use xpressive of boost library regex replacement this:

#include <iostream> #include <boost/xpressive/xpressive.hpp>  void replace(){     std::string in("a(bc) de(fg)");     sregex re = +_w >> '(' >> (s1= +_w) >> ')';     std::string out = regex_replace(in,re,"$1");     std::cout << out << std::endl; } 

what need replace captured part result of transformation function e.g.

std::string modifystring(std::string &in){     std::string out(in);     std::reverse(out.begin(),out.end());     return out; } 

so result of example provided above cb gf.

what think best approach realize this?

thanks in advance!

use

std::string modifystring(const smatch& match){     std::string out(match[1]);     std::reverse(out.begin(),out.end());     return out; }  void replace(){     std::string in("a(bc) de(fg)");     sregex re = +_w >> '(' >> (s1= +_w) >> ')';     std::string out = regex_replace(in, re, modifystring);     std::cout << out << std::endl; } 

live example

in documentation there regex_replace function view desctiption/requires