monads - Convert [IO Int] to IO [Int] in Haskell? -

i have code fits need:

f :: [io int] -> io [int] f [] = return [] f (x:xs) =    <- x   <- f xs   return (a:as) 

but thougth there predefined way (msum ?)

but can't see how.

any welcome. thx

yes, it's available in standard library under name sequence. has more general type f: monad m => [m a] -> m [a], since works monad, not io.

you find searching type [io a] -> io [a] on hoogle.