javascript ajax php display -


by using javascript ajax have passed values php page... display values after retrieving database , print in ajax page...it displaying in alert page...but need display in ajax page....

ajax coding

<script>         function optionsalert()         {             alert("call");             var xmlhttp;             var qw=document.getelementbyid('c').value;             var qw1=document.getelementbyid('c1').value;             var qw2=document.getelementbyid('unit33').value;             var qw3=document.getelementbyid('dept').value;             var qw4=document.getelementbyid('class').value;             alert(qw);             alert(qw1);             alert(qw2);             alert(qw3);             alert(qw4);              if (window.xmlhttprequest)             {// code ie7+, firefox, chrome, opera, safari                 xmlhttp=new xmlhttprequest();             }             else             {// code ie6, ie5                 xmlhttp=new activexobject("microsoft.xmlhttp");             }             xmlhttp.onreadystatechange=function()             {              if (xmlhttp.readystate==4 && xmlhttp.status==200)              {                 alert(xmlhttp.responsetext);                      if(xmlhttp.responsetext==1){                 alert("name exists" );                                   return false;                    }                        else if(xmlhttp.responsetext==0)                {                 alert("name available");                 document.login.submit();                    }              }          }              var querystring = "?q=" + qw + "&q1=" + qw1 + "&q2=" + qw2 + "&q3=" + qw3 + "&q4=" + qw4;             xmlhttp.open("get",'ques.php' + querystring,true);             xmlhttp.send();         }

php page

<?php  include('connection.php');  if(($_get['q']!='') && ($_get['q1']!='') && ($_get['q2']!='') && ($_get['q3']!='') && ($_get['q4']!='')) {     $a= mysql_query("select * unit1 unit='".$_get['q']."' , stopic='".$_get['q1']."' , qtype='".$_get['q2']."' , dept='".$_get['q3']."' , class='".$_get['q4']."'");     //$a= mysql_query("select * unit1 unit='unit1' , stopic='subtopic1' , qtype='normal questions'");     if(mysql_num_rows($a)>0)     {         while($row=mysql_fetch_array($a))         {             $a1=$row['qno'];             $a2=$row['ques'];             $a3=$row['ch1'];             $a4=$row['ch2'];             $a5=$row['ch3'];             $a6=$row['ch4'];             $a7=$row['ans'];             echo $a1."<br>";echo $a2."<br>";echo $a3."<br>";echo $a4."<br>";echo $a5."<br>";echo $a6."<br>";echo $a7."<br>";             echo 1;         }     }     else     {         echo 0;     } } ?>

below ajax coding create div element id

in ajax method

if(xmlhttp.responsetext==1){                 document.getelementbyid("id").innerhtml = "name exists";                                    return false;                    }                        else if(xmlhttp.responsetext==0)                {                 document.getelementbyid("id").innerhtml="name available";                 document.login.submit();                    }

"id" own div id


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